4(x-3)+9(2x-4)=6(x+2)-3

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Solution for 4(x-3)+9(2x-4)=6(x+2)-3 equation: 



4(x-3)+9(2x-4)=6(x+2)-3

We move all terms to the left:

4(x-3)+9(2x-4)-(6(x+2)-3)=0

We multiply parentheses

4x+18x-(6(x+2)-3)-12-36=0



We calculate terms in parentheses: -(6(x+2)-3), so:

6(x+2)-3

We multiply parentheses

6x+12-3

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We add all the numbers together, and all the variables

22x-(6x+9)-48=0

We get rid of parentheses

22x-6x-9-48=0

We add all the numbers together, and all the variables

16x-57=0

We move all terms containing x to the left, all other terms to the right

16x=57

x=57/16

x=3+9/16

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