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4(x-3)-2(x+2)=-6
We move all terms to the left:
4(x-3)-2(x+2)-(-6)=0
We add all the numbers together, and all the variables
4(x-3)-2(x+2)+6=0
We multiply parentheses
4x-2x-12-4+6=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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