4(x-3)-2x+8=2(x-4)+4

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Solution for 4(x-3)-2x+8=2(x-4)+4 equation: 



4(x-3)-2x+8=2(x-4)+4

We move all terms to the left:

4(x-3)-2x+8-(2(x-4)+4)=0

We add all the numbers together, and all the variables

-2x+4(x-3)-(2(x-4)+4)+8=0

We multiply parentheses

-2x+4x-(2(x-4)+4)-12+8=0



We calculate terms in parentheses: -(2(x-4)+4), so:

2(x-4)+4

We multiply parentheses

2x-8+4

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

2x-(2x-4)-4=0

We get rid of parentheses

2x-2x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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