4(x-3)-3(x+2)=5+2(x+2)

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Solution for 4(x-3)-3(x+2)=5+2(x+2) equation: 



4(x-3)-3(x+2)=5+2(x+2)

We move all terms to the left:

4(x-3)-3(x+2)-(5+2(x+2))=0

We multiply parentheses

4x-3x-(5+2(x+2))-12-6=0



We calculate terms in parentheses: -(5+2(x+2)), so:

5+2(x+2)

determiningTheFunctionDomain
2(x+2)+5

We multiply parentheses

2x+4+5

We add all the numbers together, and all the variables

2x+9

Back to the equation:

-(2x+9)



We add all the numbers together, and all the variables

x-(2x+9)-18=0

We get rid of parentheses

x-2x-9-18=0

We add all the numbers together, and all the variables

-1x-27=0

We move all terms containing x to the left, all other terms to the right

-x=27

x=27/-1

x=-27

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