4(x-3)-3(x-4)=5(x+2)+6

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Solution for 4(x-3)-3(x-4)=5(x+2)+6 equation: 



4(x-3)-3(x-4)=5(x+2)+6

We move all terms to the left:

4(x-3)-3(x-4)-(5(x+2)+6)=0

We multiply parentheses

4x-3x-(5(x+2)+6)-12+12=0



We calculate terms in parentheses: -(5(x+2)+6), so:

5(x+2)+6

We multiply parentheses

5x+10+6

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

x-(5x+16)=0

We get rid of parentheses

x-5x-16=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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