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4(x-3)-3x=-3(x+4)+4x
We move all terms to the left:
4(x-3)-3x-(-3(x+4)+4x)=0
We add all the numbers together, and all the variables
-3x+4(x-3)-(-3(x+4)+4x)=0
We multiply parentheses
-3x+4x-(-3(x+4)+4x)-12=0
We calculate terms in parentheses: -(-3(x+4)+4x), so:We add all the numbers together, and all the variables
-3(x+4)+4x
We add all the numbers together, and all the variables
4x-3(x+4)
We multiply parentheses
4x-3x-12
We add all the numbers together, and all the variables
x-12
Back to the equation:
-(x-12)
x-(x-12)-12=0
We get rid of parentheses
x-x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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