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4(x-3)-3x=6(x-2)
We move all terms to the left:
4(x-3)-3x-(6(x-2))=0
We add all the numbers together, and all the variables
-3x+4(x-3)-(6(x-2))=0
We multiply parentheses
-3x+4x-(6(x-2))-12=0
We calculate terms in parentheses: -(6(x-2)), so:We add all the numbers together, and all the variables
6(x-2)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
x-(6x-12)-12=0
We get rid of parentheses
x-6x+12-12=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
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