4(x-3)-5(2x-4)=2(x+2)

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Solution for 4(x-3)-5(2x-4)=2(x+2) equation: 



4(x-3)-5(2x-4)=2(x+2)

We move all terms to the left:

4(x-3)-5(2x-4)-(2(x+2))=0

We multiply parentheses

4x-10x-(2(x+2))-12+20=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

-6x-(2x+4)+8=0

We get rid of parentheses

-6x-2x-4+8=0

We add all the numbers together, and all the variables

-8x+4=0

We move all terms containing x to the left, all other terms to the right

-8x=-4

x=-4/-8

x=1/2

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