4(x-3)-5(x-8)=6(x+3)-2

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Solution for 4(x-3)-5(x-8)=6(x+3)-2 equation: 



4(x-3)-5(x-8)=6(x+3)-2

We move all terms to the left:

4(x-3)-5(x-8)-(6(x+3)-2)=0

We multiply parentheses

4x-5x-(6(x+3)-2)-12+40=0



We calculate terms in parentheses: -(6(x+3)-2), so:

6(x+3)-2

We multiply parentheses

6x+18-2

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We add all the numbers together, and all the variables

-1x-(6x+16)+28=0

We get rid of parentheses

-1x-6x-16+28=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7

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