4(x-3)-6(x+2)=13(x-6)

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Solution for 4(x-3)-6(x+2)=13(x-6) equation: 



4(x-3)-6(x+2)=13(x-6)

We move all terms to the left:

4(x-3)-6(x+2)-(13(x-6))=0

We multiply parentheses

4x-6x-(13(x-6))-12-12=0



We calculate terms in parentheses: -(13(x-6)), so:

13(x-6)

We multiply parentheses

13x-78

Back to the equation:

-(13x-78)



We add all the numbers together, and all the variables

-2x-(13x-78)-24=0

We get rid of parentheses

-2x-13x+78-24=0

We add all the numbers together, and all the variables

-15x+54=0

We move all terms containing x to the left, all other terms to the right

-15x=-54

x=-54/-15

x=3+3/5

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