4(x-3)-7=2(2x+3)+5

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Solution for 4(x-3)-7=2(2x+3)+5 equation: 


Simplifying
4(x + -3) + -7 = 2(2x + 3) + 5

Reorder the terms:
4(-3 + x) + -7 = 2(2x + 3) + 5
(-3 * 4 + x * 4) + -7 = 2(2x + 3) + 5
(-12 + 4x) + -7 = 2(2x + 3) + 5

Reorder the terms:
-12 + -7 + 4x = 2(2x + 3) + 5

Combine like terms: -12 + -7 = -19
-19 + 4x = 2(2x + 3) + 5

Reorder the terms:
-19 + 4x = 2(3 + 2x) + 5
-19 + 4x = (3 * 2 + 2x * 2) + 5
-19 + 4x = (6 + 4x) + 5

Reorder the terms:
-19 + 4x = 6 + 5 + 4x

Combine like terms: 6 + 5 = 11
-19 + 4x = 11 + 4x

Add '-4x' to each side of the equation.
-19 + 4x + -4x = 11 + 4x + -4x

Combine like terms: 4x + -4x = 0
-19 + 0 = 11 + 4x + -4x
-19 = 11 + 4x + -4x

Combine like terms: 4x + -4x = 0
-19 = 11 + 0
-19 = 11

Solving
-19 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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