4(x-3)-8=-3(-6x+4)-4x

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Solution for 4(x-3)-8=-3(-6x+4)-4x equation: 



4(x-3)-8=-3(-6x+4)-4x

We move all terms to the left:

4(x-3)-8-(-3(-6x+4)-4x)=0

We multiply parentheses

4x-(-3(-6x+4)-4x)-12-8=0



We calculate terms in parentheses: -(-3(-6x+4)-4x), so:

-3(-6x+4)-4x

We add all the numbers together, and all the variables

-4x-3(-6x+4)

We multiply parentheses

-4x+18x-12

We add all the numbers together, and all the variables

14x-12

Back to the equation:

-(14x-12)



We add all the numbers together, and all the variables

4x-(14x-12)-20=0

We get rid of parentheses

4x-14x+12-20=0

We add all the numbers together, and all the variables

-10x-8=0

We move all terms containing x to the left, all other terms to the right

-10x=8

x=8/-10

x=-4/5

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