4(x-3)-8=-3(-9x+4)-5x

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Solution for 4(x-3)-8=-3(-9x+4)-5x equation: 



4(x-3)-8=-3(-9x+4)-5x

We move all terms to the left:

4(x-3)-8-(-3(-9x+4)-5x)=0

We multiply parentheses

4x-(-3(-9x+4)-5x)-12-8=0



We calculate terms in parentheses: -(-3(-9x+4)-5x), so:

-3(-9x+4)-5x

We add all the numbers together, and all the variables

-5x-3(-9x+4)

We multiply parentheses

-5x+27x-12

We add all the numbers together, and all the variables

22x-12

Back to the equation:

-(22x-12)



We add all the numbers together, and all the variables

4x-(22x-12)-20=0

We get rid of parentheses

4x-22x+12-20=0

We add all the numbers together, and all the variables

-18x-8=0

We move all terms containing x to the left, all other terms to the right

-18x=8

x=8/-18

x=-4/9

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