4(x-3)/2=2(x+)/7

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Solution for 4(x-3)/2=2(x+)/7 equation:



4(x-3)/2=2(x+)/7
We move all terms to the left:
4(x-3)/2-(2(x+)/7)=0
We add all the numbers together, and all the variables
4(x-3)/2-(2(+x)/7)=0
We calculate fractions
4x/()+(-(2(+x)*2)/()=0
We calculate terms in parentheses: +(-(2(+x)*2)/(), so:
-(2(+x)*2)/(
We multiply all the terms by the denominator
-(2(+x)*2)
We calculate terms in parentheses: -(2(+x)*2), so:
2(+x)*2
We multiply parentheses
4x
Back to the equation:
-(4x)
Back to the equation:
+(-4x)
We get rid of parentheses
4x/()-4x=0
We multiply all the terms by the denominator
4x-4x*()=0

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