4(x-3)/2=2(x+1)/5

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Solution for 4(x-3)/2=2(x+1)/5 equation: 



4(x-3)/2=2(x+1)/5

We move all terms to the left:

4(x-3)/2-(2(x+1)/5)=0

We calculate fractions


4x/()+(-(2(x+1)*2)/()=0



We calculate terms in parentheses: +(-(2(x+1)*2)/(), so:

-(2(x+1)*2)/(

We multiply all the terms by the denominator


-(2(x+1)*2)



We calculate terms in parentheses: -(2(x+1)*2), so:

2(x+1)*2

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

-4x-4

Back to the equation:

+(-4x-4)



We get rid of parentheses

4x/()-4x-4=0

We multiply all the terms by the denominator


4x-4x*()-4*()=0

We add all the numbers together, and all the variables

4x-4x*()=0

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