4(x-3)/2=2(x+2)/6

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Solution for 4(x-3)/2=2(x+2)/6 equation:



4(x-3)/2=2(x+2)/6
We move all terms to the left:
4(x-3)/2-(2(x+2)/6)=0
We calculate fractions
4x/()+(-(2(x+2)*2)/()=0
We calculate terms in parentheses: +(-(2(x+2)*2)/(), so:
-(2(x+2)*2)/(
We multiply all the terms by the denominator
-(2(x+2)*2)
We calculate terms in parentheses: -(2(x+2)*2), so:
2(x+2)*2
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
We get rid of parentheses
-4x-8
Back to the equation:
+(-4x-8)
We get rid of parentheses
4x/()-4x-8=0
We multiply all the terms by the denominator
4x-4x*()-8*()=0
We add all the numbers together, and all the variables
4x-4x*()=0

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