4(x-3)/2=4(x+2)/12

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Solution for 4(x-3)/2=4(x+2)/12 equation: 



4(x-3)/2=4(x+2)/12

We move all terms to the left:

4(x-3)/2-(4(x+2)/12)=0

We calculate fractions


4x/()+(-(4(x+2)*2)/()=0



We calculate terms in parentheses: +(-(4(x+2)*2)/(), so:

-(4(x+2)*2)/(

We multiply all the terms by the denominator


-(4(x+2)*2)



We calculate terms in parentheses: -(4(x+2)*2), so:

4(x+2)*2

We multiply parentheses

8x+16

Back to the equation:

-(8x+16)



We get rid of parentheses

-8x-16

Back to the equation:

+(-8x-16)



We get rid of parentheses

4x/()-8x-16=0

We multiply all the terms by the denominator


4x-8x*()-16*()=0

We add all the numbers together, and all the variables

4x-8x*()=0

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