4(x-3)/5=3(2-x)/2

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Solution for 4(x-3)/5=3(2-x)/2 equation: 



4(x-3)/5=3(2-x)/2

We move all terms to the left:

4(x-3)/5-(3(2-x)/2)=0

We add all the numbers together, and all the variables

4(x-3)/5-(3(-1x+2)/2)=0

We calculate fractions


4x/()+(-(3(-1x+2)*5)/()=0



We calculate terms in parentheses: +(-(3(-1x+2)*5)/(), so:

-(3(-1x+2)*5)/(

We multiply all the terms by the denominator


-(3(-1x+2)*5)



We calculate terms in parentheses: -(3(-1x+2)*5), so:

3(-1x+2)*5

We multiply parentheses

-15x+30

Back to the equation:

-(-15x+30)



We get rid of parentheses

15x-30

Back to the equation:

+(15x-30)



We get rid of parentheses

4x/()+15x-30=0

We multiply all the terms by the denominator


4x+15x*()-30*()=0

We add all the numbers together, and all the variables

4x+15x*()=0

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