4(x-3)/8=2(x+7)/13

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Solution for 4(x-3)/8=2(x+7)/13 equation: 



4(x-3)/8=2(x+7)/13

We move all terms to the left:

4(x-3)/8-(2(x+7)/13)=0

We calculate fractions


4x/()+(-(2(x+7)*8)/()=0



We calculate terms in parentheses: +(-(2(x+7)*8)/(), so:

-(2(x+7)*8)/(

We multiply all the terms by the denominator


-(2(x+7)*8)



We calculate terms in parentheses: -(2(x+7)*8), so:

2(x+7)*8

We multiply parentheses

16x+112

Back to the equation:

-(16x+112)



We get rid of parentheses

-16x-112

Back to the equation:

+(-16x-112)



We get rid of parentheses

4x/()-16x-112=0

We multiply all the terms by the denominator


4x-16x*()-112*()=0

We add all the numbers together, and all the variables

4x-16x*()=0

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