4(x-3)5x=-48

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Solution for 4(x-3)5x=-48 equation: 



4(x-3)5x=-48

We move all terms to the left:

4(x-3)5x-(-48)=0

We add all the numbers together, and all the variables

4(x-3)5x+48=0

We multiply parentheses

20x^2-60x+48=0

a = 20; b = -60; c = +48;
Δ = b2-4ac
Δ = -602-4·20·48
Δ = -240
Delta is less than zero, so there is no solution for the equation

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