4(x-3)=(3x-4)+2

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Solution for 4(x-3)=(3x-4)+2 equation: 



4(x-3)=(3x-4)+2

We move all terms to the left:

4(x-3)-((3x-4)+2)=0

We multiply parentheses

4x-((3x-4)+2)-12=0



We calculate terms in parentheses: -((3x-4)+2), so:

(3x-4)+2

We get rid of parentheses

3x-4+2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

4x-3x+2-12=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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