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4(x-3)=(x+1)-2x
We move all terms to the left:
4(x-3)-((x+1)-2x)=0
We multiply parentheses
4x-((x+1)-2x)-12=0
We calculate terms in parentheses: -((x+1)-2x), so:We get rid of parentheses
(x+1)-2x
We add all the numbers together, and all the variables
-2x+(x+1)
We get rid of parentheses
-2x+x+1
We add all the numbers together, and all the variables
-1x+1
Back to the equation:
-(-1x+1)
4x+1x-1-12=0
We add all the numbers together, and all the variables
5x-13=0
We move all terms containing x to the left, all other terms to the right
5x=13
x=13/5
x=2+3/5
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