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4(x-3)=(x-2)
We move all terms to the left:
4(x-3)-((x-2))=0
We multiply parentheses
4x-((x-2))-12=0
We calculate terms in parentheses: -((x-2)), so:We get rid of parentheses
(x-2)
We get rid of parentheses
x-2
Back to the equation:
-(x-2)
4x-x+2-12=0
We add all the numbers together, and all the variables
3x-10=0
We move all terms containing x to the left, all other terms to the right
3x=10
x=10/3
x=3+1/3
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