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4(x-3)=-2(3x+11)
We move all terms to the left:
4(x-3)-(-2(3x+11))=0
We multiply parentheses
4x-(-2(3x+11))-12=0
We calculate terms in parentheses: -(-2(3x+11)), so:We get rid of parentheses
-2(3x+11)
We multiply parentheses
-6x-22
Back to the equation:
-(-6x-22)
4x+6x+22-12=0
We add all the numbers together, and all the variables
10x+10=0
We move all terms containing x to the left, all other terms to the right
10x=-10
x=-10/10
x=-1
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