4(x-3)=-3(6-4x)-2

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Solution for 4(x-3)=-3(6-4x)-2 equation: 



4(x-3)=-3(6-4x)-2

We move all terms to the left:

4(x-3)-(-3(6-4x)-2)=0

We add all the numbers together, and all the variables

4(x-3)-(-3(-4x+6)-2)=0

We multiply parentheses

4x-(-3(-4x+6)-2)-12=0



We calculate terms in parentheses: -(-3(-4x+6)-2), so:

-3(-4x+6)-2

We multiply parentheses

12x-18-2

We add all the numbers together, and all the variables

12x-20

Back to the equation:

-(12x-20)



We get rid of parentheses

4x-12x+20-12=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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