4(x-3)=-6(2x+1)

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Solution for 4(x-3)=-6(2x+1) equation: 



4(x-3)=-6(2x+1)

We move all terms to the left:

4(x-3)-(-6(2x+1))=0

We multiply parentheses

4x-(-6(2x+1))-12=0



We calculate terms in parentheses: -(-6(2x+1)), so:

-6(2x+1)

We multiply parentheses

-12x-6

Back to the equation:

-(-12x-6)



We get rid of parentheses

4x+12x+6-12=0

We add all the numbers together, and all the variables

16x-6=0

We move all terms containing x to the left, all other terms to the right

16x=6

x=6/16

x=3/8

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