4(x-3)=-6(2x+1)

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Solution for 4(x-3)=-6(2x+1) equation:



4(x-3)=-6(2x+1)
We move all terms to the left:
4(x-3)-(-6(2x+1))=0
We multiply parentheses
4x-(-6(2x+1))-12=0
We calculate terms in parentheses: -(-6(2x+1)), so:
-6(2x+1)
We multiply parentheses
-12x-6
Back to the equation:
-(-12x-6)
We get rid of parentheses
4x+12x+6-12=0
We add all the numbers together, and all the variables
16x-6=0
We move all terms containing x to the left, all other terms to the right
16x=6
x=6/16
x=3/8

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