4(x-3)=1/3(x+2)+5

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Solution for 4(x-3)=1/3(x+2)+5 equation: 



4(x-3)=1/3(x+2)+5

We move all terms to the left:

4(x-3)-(1/3(x+2)+5)=0



Domain of the equation: 3(x+2)+5)!=0

x∈R



We multiply parentheses

4x-(1/3(x+2)+5)-12=0

We multiply all the terms by the denominator


4x*3(x+2)-12*3(x+2)+5)-(1+5)=0

We add all the numbers together, and all the variables

4x*3(x+2)-12*3(x+2)+5)-6=0

We add all the numbers together, and all the variables

4x*3(x+2)-12*3(x+2)=0

Wy multiply elements

12x^2(x-36x(x=0

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