4(x-3)=16-2x+12+5+2x+3

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Solution for 4(x-3)=16-2x+12+5+2x+3 equation: 



4(x-3)=16-2x+12+5+2x+3

We move all terms to the left:

4(x-3)-(16-2x+12+5+2x+3)=0

We add all the numbers together, and all the variables

4(x-3)-36=0

We multiply parentheses

4x-12-36=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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