4(x-3)=2(x+4)-20

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Solution for 4(x-3)=2(x+4)-20 equation: 



4(x-3)=2(x+4)-20

We move all terms to the left:

4(x-3)-(2(x+4)-20)=0

We multiply parentheses

4x-(2(x+4)-20)-12=0



We calculate terms in parentheses: -(2(x+4)-20), so:

2(x+4)-20

We multiply parentheses

2x+8-20

We add all the numbers together, and all the variables

2x-12

Back to the equation:

-(2x-12)



We get rid of parentheses

4x-2x+12-12=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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