4(x-3)=2(x+4)-20

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Solution for 4(x-3)=2(x+4)-20 equation:



4(x-3)=2(x+4)-20
We move all terms to the left:
4(x-3)-(2(x+4)-20)=0
We multiply parentheses
4x-(2(x+4)-20)-12=0
We calculate terms in parentheses: -(2(x+4)-20), so:
2(x+4)-20
We multiply parentheses
2x+8-20
We add all the numbers together, and all the variables
2x-12
Back to the equation:
-(2x-12)
We get rid of parentheses
4x-2x+12-12=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0

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