4(x-3)=2(x-1)+x

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Solution for 4(x-3)=2(x-1)+x equation: 



4(x-3)=2(x-1)+x

We move all terms to the left:

4(x-3)-(2(x-1)+x)=0

We multiply parentheses

4x-(2(x-1)+x)-12=0



We calculate terms in parentheses: -(2(x-1)+x), so:

2(x-1)+x

We add all the numbers together, and all the variables

x+2(x-1)

We multiply parentheses

x+2x-2

We add all the numbers together, and all the variables

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

4x-3x+2-12=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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