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4(x-3)=3(x+1)-2x
We move all terms to the left:
4(x-3)-(3(x+1)-2x)=0
We multiply parentheses
4x-(3(x+1)-2x)-12=0
We calculate terms in parentheses: -(3(x+1)-2x), so:We get rid of parentheses
3(x+1)-2x
We add all the numbers together, and all the variables
-2x+3(x+1)
We multiply parentheses
-2x+3x+3
We add all the numbers together, and all the variables
x+3
Back to the equation:
-(x+3)
4x-x-3-12=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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