4(x-3)=3(x+12)

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Solution for 4(x-3)=3(x+12) equation: 



4(x-3)=3(x+12)

We move all terms to the left:

4(x-3)-(3(x+12))=0

We multiply parentheses

4x-(3(x+12))-12=0



We calculate terms in parentheses: -(3(x+12)), so:

3(x+12)

We multiply parentheses

3x+36

Back to the equation:

-(3x+36)



We get rid of parentheses

4x-3x-36-12=0

We add all the numbers together, and all the variables

x-48=0

We move all terms containing x to the left, all other terms to the right

x=48

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