4(x-3)=3(x+2)+5

Solution for 4(x-3)=3(x+2)+5 equation:

4(x-3)=3(x+2)+5

We move all terms to the left:

4(x-3)-(3(x+2)+5)=0

We multiply parentheses

4x-(3(x+2)+5)-12=0


We calculate terms in parentheses: -(3(x+2)+5), so:

3(x+2)+5

We multiply parentheses

3x+6+5

We add all the numbers together, and all the variables

3x+11

Back to the equation:

-(3x+11)


We get rid of parentheses

4x-3x-11-12=0

We add all the numbers together, and all the variables

x-23=0

We move all terms containing x to the left, all other terms to the right

x=23