4(x-3)=3x-12+x

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Solution for 4(x-3)=3x-12+x equation:


Simplifying
4(x + -3) = 3x + -12 + x

Reorder the terms:
4(-3 + x) = 3x + -12 + x
(-3 * 4 + x * 4) = 3x + -12 + x
(-12 + 4x) = 3x + -12 + x

Reorder the terms:
-12 + 4x = -12 + 3x + x

Combine like terms: 3x + x = 4x
-12 + 4x = -12 + 4x

Add '12' to each side of the equation.
-12 + 12 + 4x = -12 + 12 + 4x

Combine like terms: -12 + 12 = 0
0 + 4x = -12 + 12 + 4x
4x = -12 + 12 + 4x

Combine like terms: -12 + 12 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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