4(x-3)=4x+2-2(-5x-1)

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Solution for 4(x-3)=4x+2-2(-5x-1) equation: 



4(x-3)=4x+2-2(-5x-1)

We move all terms to the left:

4(x-3)-(4x+2-2(-5x-1))=0

We multiply parentheses

4x-(4x+2-2(-5x-1))-12=0



We calculate terms in parentheses: -(4x+2-2(-5x-1)), so:

4x+2-2(-5x-1)

determiningTheFunctionDomain
4x-2(-5x-1)+2

We multiply parentheses

4x+10x+2+2

We add all the numbers together, and all the variables

14x+4

Back to the equation:

-(14x+4)



We get rid of parentheses

4x-14x-4-12=0

We add all the numbers together, and all the variables

-10x-16=0

We move all terms containing x to the left, all other terms to the right

-10x=16

x=16/-10

x=-1+3/5

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