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4(x-3)=5(x+1)-x
We move all terms to the left:
4(x-3)-(5(x+1)-x)=0
We multiply parentheses
4x-(5(x+1)-x)-12=0
We calculate terms in parentheses: -(5(x+1)-x), so:We get rid of parentheses
5(x+1)-x
We add all the numbers together, and all the variables
-1x+5(x+1)
We multiply parentheses
-1x+5x+5
We add all the numbers together, and all the variables
4x+5
Back to the equation:
-(4x+5)
4x-4x-5-12=0
We add all the numbers together, and all the variables
-17!=0
There is no solution for this equation
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