4(x-3)=5(x/2

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Solution for 4(x-3)=5(x/2 equation:



4(x-3)=5(x/2
We move all terms to the left:
4(x-3)-(5(x/2)=0
We add all the numbers together, and all the variables
4(x-3)-(5(+x/2)=0
We multiply parentheses
4x-(5(+x/2)-12=0
We multiply all the terms by the denominator
4x*2)-12-(5(+x=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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