4(x-3)=7(2x+1)

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Solution for 4(x-3)=7(2x+1) equation: 



4(x-3)=7(2x+1)

We move all terms to the left:

4(x-3)-(7(2x+1))=0

We multiply parentheses

4x-(7(2x+1))-12=0



We calculate terms in parentheses: -(7(2x+1)), so:

7(2x+1)

We multiply parentheses

14x+7

Back to the equation:

-(14x+7)



We get rid of parentheses

4x-14x-7-12=0

We add all the numbers together, and all the variables

-10x-19=0

We move all terms containing x to the left, all other terms to the right

-10x=19

x=19/-10

x=-1+9/10

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