4(x-3)=7(2x+6)

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Solution for 4(x-3)=7(2x+6) equation: 



4(x-3)=7(2x+6)

We move all terms to the left:

4(x-3)-(7(2x+6))=0

We multiply parentheses

4x-(7(2x+6))-12=0



We calculate terms in parentheses: -(7(2x+6)), so:

7(2x+6)

We multiply parentheses

14x+42

Back to the equation:

-(14x+42)



We get rid of parentheses

4x-14x-42-12=0

We add all the numbers together, and all the variables

-10x-54=0

We move all terms containing x to the left, all other terms to the right

-10x=54

x=54/-10

x=-5+2/5

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