4(x-3)=7(x+5)

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Solution for 4(x-3)=7(x+5) equation: 



4(x-3)=7(x+5)

We move all terms to the left:

4(x-3)-(7(x+5))=0

We multiply parentheses

4x-(7(x+5))-12=0



We calculate terms in parentheses: -(7(x+5)), so:

7(x+5)

We multiply parentheses

7x+35

Back to the equation:

-(7x+35)



We get rid of parentheses

4x-7x-35-12=0

We add all the numbers together, and all the variables

-3x-47=0

We move all terms containing x to the left, all other terms to the right

-3x=47

x=47/-3

x=-15+2/3

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