4(x-3)=8(4-x)

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Solution for 4(x-3)=8(4-x) equation: 



4(x-3)=8(4-x)

We move all terms to the left:

4(x-3)-(8(4-x))=0

We add all the numbers together, and all the variables

4(x-3)-(8(-1x+4))=0

We multiply parentheses

4x-(8(-1x+4))-12=0



We calculate terms in parentheses: -(8(-1x+4)), so:

8(-1x+4)

We multiply parentheses

-8x+32

Back to the equation:

-(-8x+32)



We get rid of parentheses

4x+8x-32-12=0

We add all the numbers together, and all the variables

12x-44=0

We move all terms containing x to the left, all other terms to the right

12x=44

x=44/12

x=3+2/3

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