4(x-3)=x+3(2x-5)

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Solution for 4(x-3)=x+3(2x-5) equation: 



4(x-3)=x+3(2x-5)

We move all terms to the left:

4(x-3)-(x+3(2x-5))=0

We multiply parentheses

4x-(x+3(2x-5))-12=0



We calculate terms in parentheses: -(x+3(2x-5)), so:

x+3(2x-5)

We multiply parentheses

x+6x-15

We add all the numbers together, and all the variables

7x-15

Back to the equation:

-(7x-15)



We get rid of parentheses

4x-7x+15-12=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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