4(x-3+2)=6(x+1)+8

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Solution for 4(x-3+2)=6(x+1)+8 equation: 



4(x-3+2)=6(x+1)+8

We move all terms to the left:

4(x-3+2)-(6(x+1)+8)=0

We add all the numbers together, and all the variables

4(x-1)-(6(x+1)+8)=0

We multiply parentheses

4x-(6(x+1)+8)-4=0



We calculate terms in parentheses: -(6(x+1)+8), so:

6(x+1)+8

We multiply parentheses

6x+6+8

We add all the numbers together, and all the variables

6x+14

Back to the equation:

-(6x+14)



We get rid of parentheses

4x-6x-14-4=0

We add all the numbers together, and all the variables

-2x-18=0

We move all terms containing x to the left, all other terms to the right

-2x=18

x=18/-2

x=-9

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