4(x-33)=(3x+11)

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Solution for 4(x-33)=(3x+11) equation: 



4(x-33)=(3x+11)

We move all terms to the left:

4(x-33)-((3x+11))=0

We multiply parentheses

4x-((3x+11))-132=0



We calculate terms in parentheses: -((3x+11)), so:

(3x+11)

We get rid of parentheses

3x+11

Back to the equation:

-(3x+11)



We get rid of parentheses

4x-3x-11-132=0

We add all the numbers together, and all the variables

x-143=0

We move all terms containing x to the left, all other terms to the right

x=143

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