4(x-4)+13=3x-4

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Solution for 4(x-4)+13=3x-4 equation: 



4(x-4)+13=3x-4

We move all terms to the left:

4(x-4)+13-(3x-4)=0

We multiply parentheses

4x-(3x-4)-16+13=0

We get rid of parentheses

4x-3x+4-16+13=0

We add all the numbers together, and all the variables

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1

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