4(x-4)+21=3(x+2)

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Solution for 4(x-4)+21=3(x+2) equation: 



4(x-4)+21=3(x+2)

We move all terms to the left:

4(x-4)+21-(3(x+2))=0

We multiply parentheses

4x-(3(x+2))-16+21=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

4x-(3x+6)+5=0

We get rid of parentheses

4x-3x-6+5=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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