4(x-4)+2=-2(4-x)-8

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Solution for 4(x-4)+2=-2(4-x)-8 equation: 



4(x-4)+2=-2(4-x)-8

We move all terms to the left:

4(x-4)+2-(-2(4-x)-8)=0

We add all the numbers together, and all the variables

4(x-4)-(-2(-1x+4)-8)+2=0

We multiply parentheses

4x-(-2(-1x+4)-8)-16+2=0



We calculate terms in parentheses: -(-2(-1x+4)-8), so:

-2(-1x+4)-8

We multiply parentheses

2x-8-8

We add all the numbers together, and all the variables

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

4x-(2x-16)-14=0

We get rid of parentheses

4x-2x+16-14=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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