4(x-4)+2=3(x+1)

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Solution for 4(x-4)+2=3(x+1) equation:



4(x-4)+2=3(x+1)
We move all terms to the left:
4(x-4)+2-(3(x+1))=0
We multiply parentheses
4x-(3(x+1))-16+2=0
We calculate terms in parentheses: -(3(x+1)), so:
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
We add all the numbers together, and all the variables
4x-(3x+3)-14=0
We get rid of parentheses
4x-3x-3-14=0
We add all the numbers together, and all the variables
x-17=0
We move all terms containing x to the left, all other terms to the right
x=17

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