4(x-4)+3(x-4)=3(x+6)+2

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Solution for 4(x-4)+3(x-4)=3(x+6)+2 equation: 



4(x-4)+3(x-4)=3(x+6)+2

We move all terms to the left:

4(x-4)+3(x-4)-(3(x+6)+2)=0

We multiply parentheses

4x+3x-(3(x+6)+2)-16-12=0



We calculate terms in parentheses: -(3(x+6)+2), so:

3(x+6)+2

We multiply parentheses

3x+18+2

We add all the numbers together, and all the variables

3x+20

Back to the equation:

-(3x+20)



We add all the numbers together, and all the variables

7x-(3x+20)-28=0

We get rid of parentheses

7x-3x-20-28=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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