4(x-4)+5(8-x)=7x-(6+2x)

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Solution for 4(x-4)+5(8-x)=7x-(6+2x) equation: 



4(x-4)+5(8-x)=7x-(6+2x)

We move all terms to the left:

4(x-4)+5(8-x)-(7x-(6+2x))=0

We add all the numbers together, and all the variables

4(x-4)+5(-1x+8)-(7x-(2x+6))=0

We multiply parentheses

4x-5x-(7x-(2x+6))-16+40=0



We calculate terms in parentheses: -(7x-(2x+6)), so:

7x-(2x+6)

We get rid of parentheses

7x-2x-6

We add all the numbers together, and all the variables

5x-6

Back to the equation:

-(5x-6)



We add all the numbers together, and all the variables

-1x-(5x-6)+24=0

We get rid of parentheses

-1x-5x+6+24=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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